X^2-4.8x+2.8=0

Solution for X^2-4.8x+2.8=0 equation:

X^2-4.8X+2.8=0

a = 1; b = -4.8; c = +2.8;
Δ = b2-4ac
Δ = -4.82-4·1·2.8
Δ = 11.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.8)-\sqrt{11.84}}{2*1}=\frac{4.8-\sqrt{11.84}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.8)+\sqrt{11.84}}{2*1}=\frac{4.8+\sqrt{11.84}}{2}
$